15x^2-13x-112=0

Solution for 15x^2-13x-112=0 equation:

15x^2-13x-112=0

a = 15; b = -13; c = -112;
Δ = b2-4ac
Δ = -132-4·15·(-112)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6889}=83$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-83}{2*15}=\frac{-70}{30}
=-2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+83}{2*15}=\frac{96}{30}
=3+1/5
$